Yuming Qin's Analytic Inequalities and Their Applications in PDEs PDF

By Yuming Qin

ISBN-10: 3073123253

ISBN-13: 9783073123258

ISBN-10: 3319008307

ISBN-13: 9783319008301

ISBN-10: 3319008315

ISBN-13: 9783319008318

This e-book offers a couple of analytic inequalities and their functions in partial differential equations. those comprise necessary inequalities, differential inequalities and distinction inequalities, which play a vital position in constructing (uniform) bounds, worldwide lifestyles, large-time habit, decay charges and blow-up of strategies to numerous periods of evolutionary differential equations. Summarizing effects from an enormous variety of literature resources comparable to released papers, preprints and books, it categorizes inequalities when it comes to their diverse properties.

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Example text

15) 0 then for all t ∈ [0, b], v(t) = 0. t Proof. For all t > 0, ε > 0, t > ε, let F (t) = 0 v(s)/sds for s ∈ [ε, t]. Then we have F (t) = v(t)/t. If we add the condition F (0) = 0, then since 24 Chapter 1. Integral Inequalities limh→0+ v(h)/h = 0, we have that F (t) ∈ C[0, b]. 15), we know that F (t) = v(t)/t ≤ F (t)/t for all t > 0, that is, ≤ 1/t, t > 0. 16) over [ε, t] for any ε > 0 (t ≥ ε) yields F (t) ≤ F (ε)t/ε. 15) gives that for all t ∈ (0, b], v(t) = 0. 18), we complete the proof. , Henry [355], p.

53)) for q = 2. 4. The inequalities of Henry’s type 49 where χ(t) = Ω−1 [Ω{(m + 1)a2 (t)} + G(t)], t t t1 h2 (s)ds + · · · + G(t) = h1 (t) + 0 0 hi (t) = ηi (m + 1)Fi2 (t)R(t), ηi = 0 tm−1 hm (s)ds · · · dt1 , 0 Γ(2βi − 1) , i = 1, 2, . . 148) and T1 ∈ R+ is such that Ω{(m + 1)a(t)2 } + G(t) ∈ Dom (Ω−1 ) for all t ∈ [0, T1 ]. Proof. 149) 0 t t1 1/2 + · · · + et ηm 0 tm−1 ··· 0 1/2 2 Fm (s)e−2s ω 2 (u(s))ds · · · dt1 , 0 where ηi (i = 1, 2, . . 148). Here we have used the following estimate t 0 t1 ti−1 ··· 0 (ti−1 − s)2βi −1 e2s ds · · · dt1 0 t t1 = 0 0 2t ti−2 ··· ti−1 e2ti−1 0 σ 2βi −1 e−2σ dσ · · · dt1 0 t t1 ti−2 e ≤ 2βi Γ(2βi − 1) ··· e2ti−2 dti−1 · · · dt1 2 0 0 0 e2t Γ(2βi − 1) ≤ , i = 1, 2, .

33) with η := (1 + ε)/β. Now it is easy to prove the following existence and uniqueness theorem for abstract linear Volterra equations. 5 ([40]). Assume that α, β ∈ [0, 1) and k ∈ K(E, α). 32). 28 Chapter 1. Integral Inequalities Proof. 35). The second one can be treated in a similar manner. 29), respectively. 35). Let T ∈ J˙ be fixed. 31) that ∗k ∈ L(K∞ (E, F, β)) and that the spectral radius of this operator equals zero. 35) has at most one solution ‘on ˙ This proves the lemma. JT ’ for each T ∈ J.

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Analytic Inequalities and Their Applications in PDEs by Yuming Qin


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